Question

part a
tl
express your answer in condensed form in order of increasing orbital energy as a string without blank space between orbitals. for example, he2s^22p^6 should be entered as he2s^22p^6.
submit previous answers request answer
incorrect; try again; 2 attempts remaining

Explanation:

Step1: Find Tl's atomic number

Thallium (Tl) has atomic number 81, so it has 81 electrons.

Step2: Identify noble gas core

The noble gas preceding Tl is Xenon (Xe), with atomic number 54.

Step3: Fill remaining electrons

Subtract Xe's electrons: $81 - 54 = 27$ electrons left. Fill orbitals by energy order: $6s^2$, $4f^{14}$, $5d^{10}$, $6p^1$.

Step4: Write condensed form

Combine noble gas core and valence orbitals.

Answer:

[Xe]6s^24f^145d^106p^1