Question

part 2 of 2
what are the ccc bond angles? enter a value without units between 0° and 180°.
∠abc=
∠bcd=
∠cde=

Explanation:

Step1: Analyze double - bond geometry

In a molecule with double - bonds, the carbon atoms involved in the double - bond have a trigonal planar geometry. The bond angles around a trigonal - planar carbon are 120°.

Step2: Determine ∠abc

Carbon atom b has a double - bond and is trigonal planar. So, ∠abc = 120.

Step3: Determine ∠bcd

Carbon atom c has a double - bond and is trigonal planar. So, ∠bcd = 120.

Step4: Determine ∠cde

Carbon atom d has a double - bond and is trigonal planar. So, ∠cde = 120.

Answer:

∠abc = 120
∠bcd = 120
∠cde = 120