Question

part a: what direction? (bigger arrows show stronger forces)
part b: what is the net force and what is the direction? (do the math and include units)

Explanation:

Step1: Define positive - direction

Let the right - hand direction be positive for horizontal forces and the upward direction be positive for vertical forces.

Step2: Calculate net force for first case in Part B

For the first object in Part B with forces 6N and 2N acting horizontally, $F_{net1}=6N - 2N=4N$. The direction is to the right.

Step3: Calculate net force for second case in Part B

For the second object in Part B with two 4N forces acting horizontally, $F_{net2}=4N - 4N = 0N$. There is no net - force, so no direction.

Step4: Calculate net force for third case in Part B

For the third object in Part B with forces 6N and 8N acting horizontally, $F_{net3}=8N - 6N=2N$. The direction is to the right.

Step5: Calculate net force for fourth case in Part B

For the fourth object in Part B with 6N upward and 6N downward, $F_{net4}=6N - 6N = 0N$. There is no net - force, so no direction.

Step6: Calculate net force for fifth case in Part B

For the fifth object in Part B with 9N and 0N forces acting horizontally, $F_{net5}=9N-0N = 9N$. The direction is to the right.

Answer:

1. 4N, to the right
2. 0N, no direction
3. 2N, to the right
4. 0N, no direction
5. 9N, to the right