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Question
part 2 of 2
which violate hunds rule? check all that apply.
none of the above
To determine which electron configurations violate Hund's rule, we recall Hund's rule: electrons in degenerate orbitals (same energy) fill them singly with parallel spins before pairing up.
Analyzing each option:
- First configuration ( \( \boldsymbol{\uparrow\quad\uparrow\downarrow\quad\uparrow\quad\uparrow\downarrow\quad\uparrow\downarrow} \)):
Degenerate orbitals (each box is a degenerate orbital). Electrons first fill singly (parallel spins) then pair. Here, some orbitals have single electrons (parallel \( \uparrow \)) and others have pairs. This follows Hund’s rule (no violation).
- Second configuration ( \( \boldsymbol{\uparrow\quad\uparrow\quad\uparrow\downarrow} \)):
Three degenerate orbitals. The first two have single \( \uparrow \) electrons (parallel), but the third orbital has a pair (\( \uparrow\downarrow \)) before all orbitals have single electrons. This violates Hund’s rule (electrons paired in an orbital before all orbitals have one electron).
- Third configuration ( \( \boldsymbol{\uparrow\quad\uparrow\quad\downarrow\quad\uparrow\quad\uparrow} \)):
One orbital has a \( \downarrow \) electron while others have \( \uparrow \). Electrons in degenerate orbitals should have parallel spins when singly occupied. The \( \downarrow \) spin (opposite to \( \uparrow \)) in a singly - occupied orbital violates Hund’s rule (spin - pairing before all orbitals are singly filled, and incorrect spin alignment for single electrons).
- Fourth configuration ( \( \boldsymbol{\uparrow\downarrow\quad\uparrow\downarrow\quad\downarrow\downarrow\quad\uparrow\downarrow\quad\uparrow} \)):
Orbitals have paired electrons or a single \( \uparrow \), but one orbital has \( \downarrow\downarrow \) (invalid, as electrons in an orbital must have opposite spins, but also, the \( \downarrow\downarrow \) is a violation of Pauli exclusion principle, and also, the filling order violates Hund’s rule (pairing and incorrect spin alignment in singly - occupied - like orbitals). However, more directly, the third and second configurations clearly violate Hund’s rule, and the fourth also has issues, but let's focus on the key violations.
Correct Violations:
- The second configuration ( \( \uparrow\quad\uparrow\quad\uparrow\downarrow \)): Pairs electrons in an orbital before all degenerate orbitals have one electron.
- The third configuration ( \( \uparrow\quad\uparrow\quad\downarrow\quad\uparrow\quad\uparrow \)): Incorrect spin ( \( \downarrow \)) in a singly - occupied orbital (should be parallel \( \uparrow \) before pairing).
- The fourth configuration ( \( \uparrow\downarrow\quad\uparrow\downarrow\quad\downarrow\downarrow\quad\uparrow\downarrow\quad\uparrow \)): Has \( \downarrow\downarrow \) (Pauli violation, and also Hund’s rule violation due to incorrect filling).
But from the given checkboxes (assuming the third was pre - checked, but let's re - evaluate):
- The second row ( \( \uparrow\quad\uparrow\quad\uparrow\downarrow \)): Violates Hund’s rule (pairs too early).
- The third row ( \( \uparrow\quad\uparrow\quad\downarrow\quad\uparrow\quad\uparrow \)): Violates Hund’s rule (incorrect spin in single orbital).
- The fourth row ( \( \uparrow\downarrow\quad\uparrow\downarrow\quad\downarrow\downarrow\quad\uparrow\downarrow\quad\uparrow \)): Violates Hund’s rule (and Pauli, but Hund’s rule is about filling order/spin in degenerate orbitals; the \( \downarrow\downarrow \) is invalid, and the single \( \uparrow \) is in a context where others are paired incorrectly).
So the configurations that violate Hund’s rule…
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The configurations that violate Hund's rule are:
- The second row (with \( \uparrow\quad\uparrow\quad\uparrow\downarrow \))
- The third row (with \( \uparrow\quad\uparrow\quad\downarrow\quad\uparrow\quad\uparrow \))
- The fourth row (with \( \uparrow\downarrow\quad\uparrow\downarrow\quad\downarrow\downarrow\quad\uparrow\downarrow\quad\uparrow \))
(In the given interface, you would check the boxes for the second, third, and fourth rows. The first row does not violate Hund’s rule.)