Question

is the particle represented by the electron configuration below paramagnetic or diamagnetic?
$1s^2 2s^2 2p^6 3s^2 3p^6 4s^1 3d^5$
paramagnetic
diamagnetic

Explanation:

Step1: Identify unpaired electrons

Orbitals: $1s^2$ (paired), $2s^2$ (paired), $2p^6$ (paired), $3s^2$ (paired), $3p^6$ (paired), $4s^1$ (unpaired), $3d^5$ (5 unpaired, Hund's rule: each d orbital gets one electron first).

Step2: Count total unpaired electrons

Total unpaired electrons = $1 + 5 = 6$

Step3: Classify magnetism

Particles with unpaired electrons are paramagnetic.

Answer:

paramagnetic