Question

of the people who fished at clearwater park today, 64 had a fishing license, and 16 did not. of the people who fished at mountain view park today, 72 had a license, and 18 did not. (no one fished at both parks.) suppose that one fisher from each park is chosen at random. what is the probability that the fisher chosen from clearwater did not have a license and the fisher chosen from mountain view had a license? do not round your answer.

Explanation:

Step1: Calculate total fishers at Clearwater Park

The total number of people who fished at Clearwater Park is the sum of those with and without a license. So, $64 + 16=80$.

Step2: Calculate the probability

The probability $P$ that a fisher chosen from Clearwater Park did not have a license is the number of fishers without a license divided by the total number of fishers. So, $P=\frac{16}{80}=\frac{1}{5}$.

Answer:

$\frac{1}{5}$