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the perimeter of any rectangle in which the length is 4 more than twice…

Question

the perimeter of any rectangle in which the length is 4 more than twice the width is p = 6w + 8, where w is the width. which formula can be used to find the width given the perimeter?
a) w = p - 4
b) w = 1/6p - 8
c) w = (p + 8)/6
d) w = (p - 8)/6

Explanation:

Step1: Isolate the variable w.

Given $P = 6w+8$, first subtract 8 from both sides: $P - 8=6w$.

Step2: Solve for w.

Divide both sides by 6: $w=\frac{P - 8}{6}$.

Answer:

B) $w=\frac{P - 8}{6}$