Question

a photon has a frequency of 8.55×10^8 hz. what is the energy of this photon in joules? (h = 6.626×10^(-34) j·s)

Explanation:

Step1: Recall energy - frequency formula

The energy of a photon is given by the formula $E = h
u$, where $E$ is the energy, $h$ is Planck's constant, and $
u$ is the frequency.

Step2: Substitute the given values

We are given that $h = 6.626\times10^{-34}\ J\cdot s$ and $
u=8.55\times 10^{8}\ Hz$. Substituting these values into the formula, we get $E=(6.626\times 10^{-34}\ J\cdot s)\times(8.55\times 10^{8}\ Hz)$.

Step3: Perform the multiplication

Using the rule of exponents $a^m\times a^n=a^{m + n}$, we have $E=(6.626\times8.55)\times10^{-34 + 8}\ J$.
$6.626\times8.55 = 56.6523$ and $-34 + 8=-26$. So $E = 56.6523\times10^{-26}\ J$.
In scientific - notation, $E = 5.66523\times10^{-25}\ J$.

Answer:

$5.66523\times 10^{-25}$