Question

1. please do the following calculations and round your answer to the correct number of significant figures. include a unit in your answer.

a. 83.44 g ÷ 22 ml =
b. 50.000 m × 2.0 m =
c. 6.72 mg + 0.29 mg =

Explanation:

Step1: Solve part a

Perform division and consider significant - figures.
$83.44\ g\div22\ mL=\frac{83.44}{22}\ g/mL\approx3.8\ g/mL$ (2 significant figures as 22 has 2 significant figures)

Step2: Solve part b

Multiply the values.
$50.000\ m\times2.0\ m = 100.00\ m^{2}\approx1.0\times10^{2}\ m^{2}$ (2 significant figures as 2.0 has 2 significant figures)

Step3: Solve part c

Add the values and consider significant - figures for addition.
$6.72\ mg + 0.29\ mg=(6.72 + 0.29)\ mg=7.01\ mg$

Answer:

a. $3.8\ g/mL$
b. $1.0\times10^{2}\ m^{2}$
c. $7.01\ mg$