Question

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the net of a triangular prism and its approximate dimensions are shown in the diagram.
which measurement is closest to the total surface area of the triangular prism in square centimeters?

Explanation:

Step1: Calculate area of 2 triangles

The triangular faces have base $18$ cm and height $15.6$ cm. Area of one triangle is $\frac{1}{2} \times 18 \times 15.6$, so for 2 triangles:
$2 \times \frac{1}{2} \times 18 \times 15.6 = 18 \times 15.6 = 280.8$ $\text{cm}^2$

Step2: Calculate area of 3 rectangles

There are three rectangles: one with dimensions $18 \times 6$ cm, and two with dimensions $18 \times 6$ cm (wait, correction: the three rectangles have sides 6 cm paired with each side of the triangle: $18$ cm, $18$ cm, $18$ cm). Total area of rectangles:
$(18 \times 6) + (18 \times 6) + (18 \times 6) = 3 \times 18 \times 6 = 324$ $\text{cm}^2$

Step3: Sum all areas for total surface area

Add the area of the triangular faces and rectangular faces:
$280.8 + 324 = 604.8$ $\text{cm}^2$

Answer:

$604.8$ square centimeters (or approximately 605 square centimeters if rounding to the nearest whole number)