Question

point h is the mid - point of side fk. for the triangles to be congruent by sss, what must be the value of x? 3x - 2 2x + 4

Explanation:

Step1: Recall SSS congruence condition

For $\triangle FGH$ and $\triangle JKH$ to be congruent by SSS, $FG = JK$.

Step2: Set up the equation

Set $3x - 2=2x + 4$.

Step3: Solve the equation

Subtract $2x$ from both sides: $3x-2x-2=2x - 2x+4$, which simplifies to $x - 2=4$. Then add 2 to both sides: $x=4 + 2$. So $x = 6$.

Answer:

6