Question

pq bisects st at r. sr = 3x + 3 and st = 30. find x. (hint: because pq bisects st at r, sr and rt are congruent segments.)

Explanation:

Step1: R is midpoint of ST

ST = 2·SR

Step2: Substitute ST=30

30 = 2·SR ⇒ SR=15

Step3: Set SR=3x+3=15

3x=12 ⇒ x=4

Answer:

C. x=4