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QUESTION IMAGE

pqrs ~ fghe, find ef. ef =

Question

pqrs ~ fghe, find ef.
ef =

Explanation:

Step1: Find similarity ratio

$\text{Ratio} = \frac{PS}{HE} = \frac{6}{2} = 3$

Step2: Match corresponding sides

$EF$ corresponds to $QP$, so $\frac{QP}{EF} = 3$

Step3: Solve for $EF$

$EF = \frac{QP}{3} = \frac{12}{3} = 4$

Answer:

4