QUESTION IMAGE
Question
practice
find the area of each parallelogram. (example 1)
1.
2.
- the parallelogram - shaped learning toy belonging to marcos baby brother has the dimensions shown. what is the base length of the toy? (example 2)
- the dimensions of a parallelogram - shaped tabletop are shown. what is the distance across the tabletop? (example 3)
find the area of each trapezoid. (example 3)
5.
6.
Step1: Use parallelogram area formula
The area of a parallelogram is $A = b \times h$, where $b$ is the base and $h$ is the corresponding height.
Step1 (Problem 1): Substitute given values
Base $b=8$ m, height $h=10$ m.
$A = 8 \times 10$
Step2 (Problem 1): Calculate the area
$A = 80$
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Step1 (Problem 2): Substitute given values
Base $b=10$ in, height $h=9$ in.
$A = 10 \times 9$
Step2 (Problem 2): Calculate the area
$A = 90$
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Step1 (Problem 3): Rearrange area formula for base
$b = \frac{A}{h}$, where $A=72$ cm², $h=8$ cm.
$b = \frac{72}{8}$
Step2 (Problem 3): Calculate the base length
$b = 9$
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Step1 (Problem 4): Rearrange area formula for height
$h = \frac{A}{b}$, where $A=720$ in², $b=36$ in.
$h = \frac{720}{36}$
Step2 (Problem 4): Calculate the height
$h = 20$
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Step1 (Problem 5): Find the lower base length
Lower base $= 7 + 5 + 2 = 14$ m.
Step2 (Problem 5): Use trapezoid area formula
Trapezoid area $A = \frac{1}{2}(b_1 + b_2)h$, where $b_1=7$ m, $b_2=14$ m, $h=6$ m.
$A = \frac{1}{2}(7 + 14) \times 6$
Step3 (Problem 5): Simplify and calculate
$A = \frac{1}{2} \times 21 \times 6 = 63$
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Step1 (Problem 6): Find the lower base length
Lower base $= 9 + 3 + 3 = 15$ ft.
Step2 (Problem 6): Use trapezoid area formula
Trapezoid area $A = \frac{1}{2}(b_1 + b_2)h$, where $b_1=9$ ft, $b_2=15$ ft, $h=6$ ft.
$A = \frac{1}{2}(9 + 15) \times 6$
Step3 (Problem 6): Simplify and calculate
$A = \frac{1}{2} \times 24 \times 6 = 72$
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