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practice a. find the surface area of this right rectangular prism. dime…

Question

practice a. find the surface area of this right rectangular prism. dimensions are in
b. find the surface area of this right triangular prism. dimensions are in feet
c. a right circular cylinder has a radius of 20 centimeters and a length of 200 cm as shown. find the surface area of the right circular cylinder.
d. a base of the right solid 10 meters high is shown. find the surface area of the ng dimensions are in meters. (remember that the lateral surface area of a right solid is to the perimeter of a base times the height.)

  1. (a) what do we call the total area of all exposed surfaces of a geometric solid? (b) how do you find the lateral surface area of any right solid?

Explanation:

Step1: Recall surface - area formula for rectangular prism

The surface - area formula of a rectangular prism with length $l$, width $w$, and height $h$ is $SA = 2(lw+lh + wh)$. For the rectangular prism with $l = 4$, $w = 3$, and $h = 2$, we substitute these values: $SA=2(4\times3 + 4\times2+3\times2)$.

Step2: Calculate the products inside the parentheses

$4\times3 = 12$, $4\times2 = 8$, and $3\times2 = 6$. So, $SA = 2(12 + 8+6)$.

Step3: Add the numbers inside the parentheses

$12 + 8+6=26$. Then $SA = 2\times26=52$ square units.

Step4: Recall surface - area formula for right - triangular prism

The surface area of a right - triangular prism is $SA=2\times(\text{area of base})+\text{lateral surface area}$. The base is a right - triangle with legs $a = 8$ and $b = 6$, so the area of the base $A_{base}=\frac{1}{2}\times8\times6 = 24$ square feet. The lateral surface area: the three rectangles have areas $6\times12$, $8\times12$, and $10\times12$. The lateral surface area $A_{lateral}=(6 + 8+10)\times12=24\times12 = 288$ square feet. Then $SA = 2\times24+288=48 + 288=336$ square feet.

Step5: Recall surface - area formula for right - circular cylinder

The surface area of a right - circular cylinder is $SA = 2\pi r^{2}+2\pi rl$, where $r = 20$ cm and $l = 200$ cm. $2\pi r^{2}=2\pi\times20^{2}=2\pi\times400 = 800\pi$ square cm, and $2\pi rl=2\pi\times20\times200 = 8000\pi$ square cm. So, $SA=800\pi + 8000\pi=8800\pi\approx8800\times3.14 = 27632$ square cm.

Step6: Analyze the composite solid

The base of the solid has a perimeter $P$. The base is composed of a semi - circle and a right - triangle. The perimeter of the semi - circle is $\pi r=\pi\times3$ and the sides of the right - triangle are $8$, $10$. The perimeter of the base $P=8 + 10+3\pi$. The lateral surface area $A_{lateral}=(8 + 10+3\pi)\times10=180 + 30\pi$ square meters. The area of the semi - circle $A_{semicircle}=\frac{1}{2}\pi r^{2}=\frac{1}{2}\pi\times3^{2}=\frac{9\pi}{2}$ square meters, and the area of the right - triangle $A_{triangle}=\frac{1}{2}\times8\times3 = 12$ square meters. The total surface area $SA=2\times(\frac{9\pi}{2}+12)+180 + 30\pi=9\pi+24 + 180+30\pi=49\pi + 204\approx49\times3.14+204=153.86+204 = 357.86$ square meters.

Step7: Answer part 1(a)

The total area of all exposed surfaces of a geometric solid is called the surface area.

Step8: Answer part 1(b)

The lateral surface area of a right solid is the perimeter of a base times the height.

Answer:

a. 52 square units
b. 336 square feet
c. $8800\pi\approx27632$ square cm
d. $49\pi + 204\approx357.86$ square meters

  1. (a) Surface area

(b) The perimeter of a base times the height.