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the pre - image, $delta$stu, has undergone a type of transformation cal…

Question

the pre - image, $delta$stu, has undergone a type of transformation called a rigid transformation to produce the image, $delta$vwx. compare the measures of the triangles by dragging the image to the pre - image. which measures are equal? check all that apply.
st = vw
su = vx
tu = wx
$mangle$sut = $mangle$vxw
$mangle$tsu = $mangle$wvx
$mangle$uts = $mangle$xwv

Explanation:

Step1: Recall rigid - transformation property

Rigid transformations (translations, rotations, reflections) preserve side - lengths and angle - measures.

Step2: Match corresponding sides

Corresponding sides of pre - image $\triangle STU$ and image $\triangle VWX$ are equal. So, $ST = VW$, $SU = VX$, $TU = WX$.

Step3: Match corresponding angles

Corresponding angles of pre - image $\triangle STU$ and image $\triangle VWX$ are equal. So, $m\angle SUT=m\angle VXW$, $m\angle TSU = m\angle WVX$, $m\angle UTS=m\angle XWV$.

Answer:

ST = VW
SU = VX
TU = WX
$m\angle SUT = m\angle VXW$
$m\angle TSU = m\angle WVX$
$m\angle UTS = m\angle XWV$