Question

predict the geometries of the following ion.
so₄²⁻
part 1 of 2
electron domain geometry
select
linear
trigonal planar
tetrahedral
part 2
molecu
trigonal bipyramidal
octahedral
select

Explanation:

Step1: Determine central atom

The central atom in $SO_{4}^{2 -}$ is sulfur (S).

Step2: Calculate electron - domain number

Sulfur has 6 valence electrons, each oxygen contributes 6 valence electrons and there are 4 oxygen atoms, and there is a 2 - charge (2 extra electrons). The total number of valence electrons is $6 + 4\times6+2=32$. The number of bonding pairs around S is 4 (4 S - O bonds), and the number of lone pairs on S is 0. The electron - domain number (bonding pairs + lone pairs) around S is 4.

Step3: Identify electron - domain geometry

Based on the VSEPR (Valence - Shell Electron - Pair Repulsion) theory, when the electron - domain number is 4 and there are no lone pairs on the central atom, the electron - domain geometry is tetrahedral.

Step4: Identify molecular geometry

Since there are no lone pairs on the central atom and 4 bonding pairs, the molecular geometry is also tetrahedral.

Answer:

Part 1 of 2
Electron Domain Geometry: tetrahedral
Part 2
Molecular Geometry: tetrahedral