Question

problem 4
determine the values of ( a ), ( b ), ( c ), and ( d ).

Explanation:

Step1: Solve for $a$

The first bar sums to 60:
$$3a + 12 = 60$$
$$3a = 60 - 12$$
$$3a = 48$$
$$a = \frac{48}{3} = 16$$

Step2: Solve for $b$

The second bar equals the first bar (60):
$$4(b+5) = 60$$
$$b+5 = \frac{60}{4} = 15$$
$$b = 15 - 5 = 10$$

Step3: Solve for $c$

The third bar equals the first bar (60):
$$(a+b) + c = 60$$
Substitute $a=16$, $b=10$:
$$16+10 + c = 60$$
$$26 + c = 60$$
$$c = 60 - 26 = 34$$

Step4: Solve for $d$

The fourth bar equals the first bar (60):
$$3c + d = 60$$
Substitute $c=34$:
$$3(34) + d = 60$$
$$102 + d = 60$$
$$d = 60 - 102 = -42$$

Answer:

$a=16$, $b=10$, $c=34$, $d=-42$