Question

problem give iupac names for the following cycloalkanes: 4 - 1 (a) (b) (c) (d) (e) (f)

Explanation:

Step1: Identify parent - ring

For (a), the parent - ring is cyclohexane.

Step2: Locate and name substituents

There are two methyl groups at 1 and 4 positions. So the IUPAC name is 1,4 - dimethylcyclohexane.

Step3: For (b), the parent - ring is cyclopentane

There is a methyl group at position 1 and a propyl group at position 3. So the IUPAC name is 1 - methyl - 3 - propylcyclopentane.

Step4: For (c), the parent - ring is cyclobutane

There is an isopropyl group attached. So the IUPAC name is isopropylcyclobutane.

Step5: For (d), the parent - ring is a bicyclic system

Numbering starts from the bridge - head carbon. There is an ethyl group at position 2 and a bromo group at position 6. So the IUPAC name is 2 - ethyl - 6 - bromobicyclo[3.2.0]heptane.

Step6: For (e), the parent - ring is cyclohexane

There is a methyl group at position 1 and an isopropyl group at position 4. So the IUPAC name is 1 - methyl - 4 - isopropylcyclohexane.

Step7: For (f), the parent - ring is cyclooctane

There is a bromo group at position 1, a methyl group at position 4 and a tert - butyl group at position 5. So the IUPAC name is 1 - bromo - 4 - methyl - 5 - tert - butylcyclooctane.

Answer:

(a) 1,4 - dimethylcyclohexane
(b) 1 - methyl - 3 - propylcyclopentane
(c) isopropylcyclobutane
(d) 2 - ethyl - 6 - bromobicyclo[3.2.0]heptane
(e) 1 - methyl - 4 - isopropylcyclohexane
(f) 1 - bromo - 4 - methyl - 5 - tert - butylcyclooctane