Question

problem: an ice hockey player hits a puck of mass 0.15 kilograms with a force of 100 newtons in the horizontal direction. what is the acceleration produced by the force in the horizontal direction? part c: modify the equation to solve for (a_x). remember that only one force is involved. use your keyboard and the keypad to enter your answer. then click done. (f_x = ma_x)

Explanation:

Step1: Identify given values

$F_x = 100$ N, $m=0.15$ kg

Step2: Rearrange formula for acceleration

We have $F_x = ma_x$, so $a_x=\frac{F_x}{m}$

Step3: Substitute values

$a_x=\frac{100}{0.15}=\frac{100}{\frac{3}{20}}=\frac{2000}{3}\approx 666.67$ m/s²

Answer:

$\frac{2000}{3}$ m/s² or approximately $666.67$ m/s²