Question

problems 9-10: solve each equation.

1. $\frac{3y - 6}{9}=\frac{4 - 2y}{-3}$
2. $0.3(x - 10) - 1.8 = 2.7x$

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Explanation:

Step1: Cross-multiply to eliminate denominators

$(3y - 6)(-3) = (4 - 2y)(9)$

Step2: Expand both sides of the equation

$-9y + 18 = 36 - 18y$

Step3: Isolate y terms on left side

$-9y + 18y = 36 - 18$

Step4: Simplify to solve for y

$9y = 18$
$y = \frac{18}{9} = 2$

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Step1: Distribute the 0.3 to the parentheses

$0.3x - 3 - 1.8 = 2.7x$

Step2: Combine constant terms

$0.3x - 4.8 = 2.7x$

Step3: Isolate x terms on right side

$-4.8 = 2.7x - 0.3x$

Step4: Simplify to solve for x

$-4.8 = 2.4x$
$x = \frac{-4.8}{2.4} = -2$

Answer:

For equation 9: $y=2$
For equation 10: $x=-2$