Question

1. in procedure 2 part 2: each “corner” on the velocity vs. time graph shows the speed of the cardboard changing from zero to some value, or vice versa. what must the acceleration (the instantaneous change in velocity with time) look like at these times? explain!

Explanation:

Step1: Acceleration is v-t slope

Acceleration \( a = \frac{dv}{dt} \), slope of velocity-time graph.

Step2: "Corner" means slope abrupt change

At "corner", slope (acceleration) changes suddenly.

Step3: Acceleration has instantaneous spike

Abrupt change leads to acceleration with instantaneous large value (infinite ideal).

Answer:

Acceleration has an instantaneous large (infinite in ideal) value at these times.