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Question
progress: the movement of the progress bar may be uneven because questions can be worth more or less (including zero) depending on your answer. square the binomial: ((8y - 5)^2) (64y^2 - 40y + 25) (64y^2 + 80y - 25) (64y^2 - 80y + 25) (64y^2 + 25)
Step1: Recall the formula for squaring a binomial
The formula for squaring a binomial \((a - b)^2\) is \(a^2 - 2ab + b^2\). In the given binomial \((8y - 5)^2\), we have \(a = 8y\) and \(b = 5\).
Step2: Calculate \(a^2\)
Substitute \(a = 8y\) into \(a^2\). So, \(a^2=(8y)^2 = 8^2\times y^2 = 64y^2\).
Step3: Calculate \(-2ab\)
Substitute \(a = 8y\) and \(b = 5\) into \(-2ab\). So, \(-2ab=-2\times(8y)\times5=-80y\).
Step4: Calculate \(b^2\)
Substitute \(b = 5\) into \(b^2\). So, \(b^2 = 5^2 = 25\).
Step5: Combine the terms
Now, combine the results from Step 2, Step 3, and Step 4. We get \((8y - 5)^2=64y^2-80y + 25\).
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\(64y^2 - 80y + 25\) (corresponding to the option: \(64y^2 - 80y + 25\))