Question

the proof that δacb ≅ δecd is shown. given: ae and db bisect each other at c. prove: δacb ≅ δecd what is the missing statement in the proof? ∠bac ≅ ∠dec ∠acd ≅ ∠ecb ∠acb ≅ ∠ecd ∠bca ≅ ∠dca

Explanation:

Step1: Recall vertical - angle property

Vertical angles are formed when two lines intersect. When $\overline{AE}$ and $\overline{DB}$ intersect at $C$, $\angle ACB$ and $\angle ECD$ are vertical angles.

Step2: Apply vertical - angle congruence

Vertical angles are always congruent. So, $\angle ACB\cong\angle ECD$.

Answer:

$\angle ACB\cong\angle ECD$