Question

proving the law of sines
two right - triangles, △abd and △acd, were created from △abc by constructing ad⊥cb.
follow these steps to prove that $\frac{sin(b)}{b}=\frac{sin(c)}{c}$.

1. for △abd, sin(b) =
2. multiply both sides of the equation by c and simplify. the equation sin(b)=\frac{h}{c} becomes

Explanation:

Step1: Multiply both sides by c

Given $\sin(B)=\frac{h}{c}$, when we multiply both sides by $c$, we get $c\sin(B)=h$.

Answer:

$c\sin(B)=h$