Question

proving theorem 2.1 copy and complete the proof for two of the cases of the properties of segment congruence theorem. 6. reflexive property of segment congruence given ► ef is a line segment prove ► $overline{ef}congoverline{ef}$ statements reasons 1. $ef = ef$ 1. ？ 2. ？ 2. definition of congruent segments

Explanation:

Step1: Recall equality property

Any quantity is equal to itself. This is the reflexive property of equality. So for the statement $EF = EF$, the reason is "Reflexive property of equality".

Step2: Apply congruence - definition

If two segments have the same length (i.e., are equal in length), they are congruent. Since $EF = EF$, by the definition of congruent segments, we can conclude that $\overline{EF}\cong\overline{EF}$. So the missing statement in the second - row is $\overline{EF}\cong\overline{EF}$.

Answer:

1. Reflexive property of equality
2. $\overline{EF}\cong\overline{EF}$