Question

pure water at 25°c
ionizes in the presence of acid to form an equilibrium in which h₃o⁺=oh⁻=10⁷m.
ionizes in the presence of acid to form an equilibrium in which h₃o⁺=oh⁻=10⁻⁷m.
self - ionizes to form an equilibrium in which h₃o⁺=oh⁻=10⁷m.
self - ionizes to form an equilibrium in which h₃o⁺=oh⁻=10⁻⁷m.

Explanation:

Pure water undergoes self - ionization at 25°C. The auto - ionization of water results in an equilibrium where the concentration of hydronium ions $[H_3O^+]$ is equal to the concentration of hydroxide ions $[OH^-]$, and at 25°C, $[H_3O^+]=[OH^-]=10^{-7}M$.

Answer:

self - ionizes to form an equilibrium in which $[H_3O^+]=[OH^-]=10^{-7}M$