Question

q10 what is the product of (4 + 3i)(4 - 3i)?

Explanation:

Step1: Apply the formula (a + b)(a - b)=a^2 - b^2

Here a = 4 and b = 3i, so (4 + 3i)(4 - 3i)=4^2-(3i)^2

Step2: Calculate the squares

4^2 = 16, and (3i)^2=3^2\times i^2. Since i^2=- 1, then (3i)^2 = 9\times(-1)=-9

Step3: Subtract the results

16-(-9)=16 + 9 = 25

Answer:

25