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q1a: what do star trails look like at the north pole? does it... simula…

Question

q1a: what do star trails look like at the north pole? does it... simulation courtesy of astronomy education at the university of nebraska - lincoln (https://astro.unl.edu) note: you can access a full - screen version of this tool here. - part (a) at what latitude do stars appear to rise vertically with respect to the eastern horizon? 0° correct! - part (b) at what latitude do all stars appear to travel in circles around the sky parallel to the horizon, never rising or setting? (please note: select all that apply.) 90°n, 90°s correct! - part (c) at which latitude do stars appear to rise in the east and follow paths toward the northern part of the sky? 90°s stars always rise in the east, travel toward the south, and set in the west, regardless of latitude. 90°n 45°s 0° submit hint feedback i give up! 4 submission(s) remaining hints: 0% deduction per hint. hints remaining: 1 feedback: 0% deduction per feedback. grade summary deductions 0% potential 100% submissions attempt(s) remaining: 4 25% deduction per attempt detailed view

Explanation:

Step1: Understand celestial - motion principles

The motion of stars as seen from different latitudes is determined by the Earth's rotation and the observer's position on the Earth. At the equator ($0^{\circ}$ latitude), the celestial equator is perpendicular to the horizon, so stars rise vertically with respect to the eastern horizon.

Step2: Analyze polar - latitude cases

At the North Pole ($90^{\circ}N$) and South Pole ($90^{\circ}S$), the axis of the Earth's rotation is directly overhead. So all stars appear to travel in circles parallel to the horizon, never rising or setting.

Step3: Consider the case of stars rising in the east and moving north

At the South Pole ($90^{\circ}S$), stars rise in the east and follow paths toward the northern part of the sky because the observer is at the southern - most point of the Earth and the north is in the opposite direction of the south.

Answer:

$90^{\circ}S$