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a quadrilateral (appearing as a parallelogram) is drawn on a grid with …

Question

a quadrilateral (appearing as a parallelogram) is drawn on a grid with horizontal and vertical lines, with vertices at grid intersections.

Explanation:

Response

Assuming the problem is to find the area of the parallelogram on the grid (where each grid square has a side length of 1 unit).

Step1: Identify base and height

The base of the parallelogram (vertical side) spans 4 grid units (from y - coordinate 1 to y - coordinate 5, for example), so base \( b = 4 \). The horizontal distance between the two vertical - like sides (height) is 2 grid units (since the horizontal shift between the left and right sides is 2 units), so height \( h=2 \).
The formula for the area of a parallelogram is \( A = b\times h \).

Step2: Calculate the area

Substitute \( b = 4 \) and \( h = 2 \) into the formula: \( A=4\times2 = 8 \).

Answer:

The area of the parallelogram is 8 square units.