1. quadrilateral defg is a parallelogram. given
2. $\overline{de} \parallel \overline{gf}$ $\overline{dg} \parallel \overline{ef}$ definition of a parallelogram
3. draw $\overline{df}$ and $\overline{ge}$. these line segments are transversals cutting two pairs of parallel lines: $\overleftrightarrow{de}$ and $\overleftrightarrow{gf}$ and $\overleftrightarrow{dg}$ and $\overleftrightarrow{ef}$. drawing line segments
4. place point h where $\overline{df}$ and $\overline{ge}$ intersect. defining a point
5. $\angle hgd \cong \angle hef$ $\angle hdg \cong \angle hfe$
6. $\overline{dg} \cong \overline{ef}$ opposite sides of a parallelogram are congruent.
7. asa criterion for congruence
8. $\overline{gh} \cong \overline{eh}$ $\overline{dh} \cong \overline{fh}$ corresponding sides of congruent triangles are congruent.
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what is the missing statement for step 7 in this proof?
a. $\triangle dgh \cong \triangle feh$
b. $\triangle ghf \cong \triangle ehd$
c. $\triangle dgf \cong \triangle fed$
d. $\triangle def \cong \triangle edg$

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Accepted Answer

# Explanation:
## Step1: Identify congruent parts
From step 5: $\angle HGD \cong \angle HEF$, $\angle HDG \cong \angle HFE$; From step 6: $\overline{DG} \cong \overline{EF}$
## Step2: Match to ASA congruence
ASA requires two pairs of congruent angles and the included congruent side. The included side between the angles in $	riangle DGH$ and $	riangle FEH$ is $\overline{DG}$ and $\overline{EF}$, so the triangles are $	riangle DGH \cong 	riangle FEH$.
# Answer:
A. $	riangle DGH \cong 	riangle FEH$

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QUESTION IMAGE

Question

Explanation:

Step1: Identify congruent parts

Step2: Match to ASA congruence

Answer: