Question

1. quadrilateral mnop with vertices m(3, -1), n(8, -4), o(6, -6), and p(1, -7); 180° rotation m (_, _) n (_, _) o (_, _) p (_, _) © gina wilson (all things algebra®, llc). 20

Explanation:

Step1: Recall rotation rule

The rule for a 180 - degree rotation about the origin is $(x,y)\to(-x,-y)$.

Step2: Find $M'$

For $M(3, - 1)$, applying the rule: $x = 3,y=-1$, so $M'(-3,1)$.

Step3: Find $N'$

For $N(8,-4)$, with $x = 8,y = - 4$, then $N'(-8,4)$.

Step4: Find $O'$

For $O(6,-6)$, as $x = 6,y=-6$, we get $O'(-6,6)$.

Step5: Find $P'$

For $P(1,-7)$, since $x = 1,y=-7$, we have $P'(-1,7)$.

Answer:

$M'(-3,1)$
$N'(-8,4)$
$O'(-6,6)$
$P'(-1,7)$