Question

a quadrilateral has vertices (0, 0), (-8, 0), (0, -6), and (-8, -6). complete the equation with the vertical line of symmetry that will carry the quadrilateral onto itself (1 point)

Explanation:

Step1: Identify x - coordinates of vertices

The x - coordinates of the vertices are \(x_1 = 0\), \(x_2=-8\), \(x_3 = 0\), \(x_4=-8\).

Step2: Find the mid - point of the horizontal distance

The mid - point of the horizontal distance between the left - most and right - most points gives the vertical line of symmetry. The formula for the mid - point of two x - values \(x_1\) and \(x_2\) is \(x=\frac{x_1 + x_2}{2}\). Here, \(x_1 = 0\) and \(x_2=-8\), so \(x=\frac{0+( - 8)}{2}=-4\).

Answer:

\(x = - 4\)