Question

question 10
identify the best lewis structure for no₂⁺.
:o—n—o: ⁺
:o=n=o: ⁺
:o—n—o: ⁺
:o=n—o: ⁺
question 11
how many bonds are present between the nitrogen atoms in n₂f₂?
0
3
1
2

Explanation:

Step1: Calculate valence electrons for NO₂⁺

Valence e⁻: 5(N) + 2×6(O) -1(+charge)=16.

Step2: Analyze Lewis structure options

Option with double bonds (:O=N=O:⁺) has 8e⁻ around N (2 double bonds) and O (2 bonds + 2 lone pairs), satisfying octet. Formal charges: N=+1, O=0, total +1.

Step1: Determine N₂F₂ structure

N₂F₂ has N-N bond. Each N bonds to F (single) and needs octet.

Step2: Count bonds between N atoms

N atoms share 2 pairs (double bond) to satisfy octet (4e⁻ from bonds + 4e⁻ lone pairs).

Answer:

B. [:O=N=O:]+