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Question
question 3 (10 points)
how many atoms are present in 12.0 g of carbon
a 6.02×10²³
b 1.20×10²⁴
c 5.99×10²³
d 1.00×10²³
Step1: Calculate moles of C
Molar mass of C is 12.0 g/mol.
$\text{Moles of C} = \frac{\text{Mass}}{\text{Molar Mass}} = \frac{12.0\ \text{g}}{12.0\ \text{g/mol}} = 1.00\ \text{mol}$
Step2: Calculate number of atoms
Use Avogadro's number $N_A = 6.022\times10^{23}\ \text{atoms/mol}$.
$\text{Number of atoms} = \text{Moles} \times N_A = 1.00\ \text{mol} \times 6.022\times10^{23}\ \text{atoms/mol} \approx 5.99\times10^{23}\ \text{atoms}$
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c. $5.99\times10^{23}$