Question

question 6 of 10
select the two binomials that are factors of this trinomial.
$x^2 + 6x + 8$

a. $x + 8$
b. $x + 4$
c. $x - 4$
d. $x + 2$

Explanation:

Step1: Recall factoring trinomials

To factor \(x^{2}+bx + c\), we find two numbers that multiply to \(c\) and add to \(b\). Here, \(b = 6\) and \(c=8\).
We need two numbers that multiply to \(8\) and add to \(6\). The numbers are \(4\) and \(2\) since \(4\times2 = 8\) and \(4 + 2=6\).

Step2: Write the factored form

So, \(x^{2}+6x + 8=(x + 4)(x + 2)\).

Answer:

B. \(x + 4\), D. \(x + 2\)