Question

question 7 of 10
what is the distance between the points (3, 7) and (15, 16) on a coordinate plane?
a. 15 units
b. 13 units
c. 17 units
d. 21 units

Explanation:

Step1: Identify distance formula

The distance formula between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$.

Step2: Substitute the given points

Here $x_1 = 3,y_1 = 7,x_2=15,y_2 = 16$. So $d=\sqrt{(15 - 3)^2+(16 - 7)^2}=\sqrt{12^2 + 9^2}$.

Step3: Calculate the squares

$12^2=144$ and $9^2 = 81$, so $d=\sqrt{144 + 81}=\sqrt{225}$.

Step4: Find the square - root

$\sqrt{225}=15$, so the distance is 15 units.

Answer:

A. 15 units