Question

question 1 of 10 what is the measure of $overparen{jkl}$? 93° a. 267° b. 174° c. 186° d. 87°

Explanation:

Step1: Recall inscribed - angle theorem

The measure of an inscribed angle is half the measure of its intercepted arc.
Let the measure of arc $\widehat{JL}$ be $x$. The inscribed angle $\angle JKL = 93^{\circ}$. According to the inscribed - angle theorem, $\angle JKL=\frac{1}{2}\text{measure of arc }\widehat{JL}$, so $93^{\circ}=\frac{1}{2}x$.

Step2: Solve for the measure of arc $\widehat{JL}$

Multiply both sides of the equation $93^{\circ}=\frac{1}{2}x$ by 2. We get $x = 186^{\circ}$, which is the measure of arc $\widehat{JL}$. Since $\widehat{JL}=\widehat{JKL}$, the measure of $\widehat{JKL}$ is $186^{\circ}$.

Answer:

C. 186°