Question

question 8 of 10 which equation represents a chemical reaction that obeys the law of conservation of matter? o c6h12o6 + o2 → co2 + h2o o c6h12o6 + 8 o2 → 6 co2 + 8 h2o o c6h12o6 + 12 o2 → 3 co2 + 8 h2o o c6h12o6 + 6 o2 → 6 co2 + 6 h2o o 2 c6h12o6 + 6 o2 → 12 co2 + 6 h2o

Explanation:

Step1: Check carbon atoms balance

For a chemical - reaction to obey the law of conservation of matter, the number of atoms of each element on the reactant side must equal the number of atoms of the same element on the product side. In $C_6H_{12}O_6$, there are 6 carbon atoms. In $CO_2$, each molecule has 1 carbon atom.

Step2: Check hydrogen atoms balance

In $C_6H_{12}O_6$, there are 12 hydrogen atoms. In $H_2O$, each molecule has 2 hydrogen atoms. So, for 12 hydrogen atoms in the reactant, we need 6 $H_2O$ molecules in the product.

Step3: Check oxygen atoms balance

In $C_6H_{12}O_6$, there are 6 oxygen atoms. In $O_2$, each molecule has 2 oxygen atoms. In $CO_2$, each molecule has 2 oxygen atoms and in $H_2O$, each molecule has 1 oxygen atom.
For the reaction $C_6H_{12}O_6+6O_2
ightarrow6CO_2 + 6H_2O$:

• Carbon: 6 atoms on the left - hand side ($C_6H_{12}O_6$) and 6 atoms on the right - hand side ($6\times1$ in $6CO_2$).
• Hydrogen: 12 atoms on the left - hand side ($C_6H_{12}O_6$) and $6\times2 = 12$ atoms on the right - hand side ($6H_2O$).
• Oxygen: $6+(6\times2)=18$ atoms on the left - hand side and $(6\times2)+(6\times1)=18$ atoms on the right - hand side.

Answer:

$C_6H_{12}O_6+6O_2
ightarrow6CO_2 + 6H_2O$