Question

question 11 of 30
avogadro’s law relates the volume of a gas to the number of moles of gas when temperature and pressure are constant. according to this law, how many moles of gaseous product would be produced by 2 moles of gaseous reactants if the volume of the gases doubled?

a. 4 moles gaseous product
b. 2 moles gaseous product
c. 8 moles gaseous product
d. 1 mole gaseous product

Explanation:

Step1: Recall Avogadro's Law

Avogadro's Law states that at constant temperature and pressure, the volume of a gas ($V$) is directly proportional to the number of moles of the gas ($n$), i.e., $\frac{V_1}{n_1}=\frac{V_2}{n_2}$.

Step2: Identify given values

We know that initially, the number of moles of gaseous reactants $n_1 = 2$ moles. The volume doubles, so if the initial volume is $V_1$, the final volume $V_2=2V_1$. We need to find $n_2$.

Step3: Apply the law

Substitute the values into the formula $\frac{V_1}{n_1}=\frac{V_2}{n_2}$. So, $\frac{V_1}{2}=\frac{2V_1}{n_2}$. Cross - multiply: $V_1\times n_2=2\times2V_1$.

Step4: Solve for $n_2$

Divide both sides by $V_1$ (assuming $V_1
eq0$, which is valid for a gas). We get $n_2 = 4$ moles.

Answer:

A. 4 moles gaseous product