Question

question 11(multiple choice worth 2 points) (comparing data mc) the tables represent the points earned in each game for a season by two football teams. jaguars: 3, 14, 7; 7, 21, 10; 17, 6, 14; 24, 21, 7; 10, 17, 3. eagles: 3, 24, 14; 27, 10, 13; 10, 21, 24; 17, 27, 7; 40, 37, 55. which team had the best overall record for the season? determine the best measure of center to compare, and explain your answer. eagles; they have a larger median value of 21 points. jaguars; they have a larger median value of 10 points. eagles; they have a larger mean value of about 22 points. jaguars; they have a larger mean value of about 12.1 points.

Explanation:

Step1: Calculate the mean for Jaguars

First, find the sum of all points for Jaguars: $3 + 14+7+7+21+10+17+6+14+24+21+7+10+17+3=178$. There are $n = 15$ data - points. The mean $\bar{x}_{Jaguars}=\frac{178}{15}\approx11.9$.

Step2: Calculate the mean for Eagles

Find the sum of all points for Eagles: $3+24 + 14+27+10+13+10+21+24+17+27+7+40+37+55 = 339$. There are $n = 15$ data - points. The mean $\bar{x}_{Eagles}=\frac{339}{15}=22.6$.

Step3: Calculate the median for Jaguars

Arrange the Jaguars' data in ascending order: $3,3,6,7,7,7,10,10,14,14,17,17,21,21,24$. The median (the 8th value in a set of 15 values) is $10$.

Step4: Calculate the median for Eagles

Arrange the Eagles' data in ascending order: $3,7,10,10,13,14,17,21,24,24,27,27,37,40,55$. The median (the 8th value in a set of 15 values) is $21$.

Since the Eagles have a larger median value of $21$ points, the best measure of center to compare in this case (as the data may have outliers which can affect the mean) is the median.

Answer:

Eagles; they have a larger median value of 21 points