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Question
question 5 of 15 a gas sample in a syringe has a volume of 45.0 ml at 0.800 atm and 295 k. the syringe is compressed until the pressure becomes 2.40 atm and the temperature increases to 310 k. what is the final volume?
1: ( p_1 )
a. 295 k
b. 310 k
c. 0.800 atm
d. unknown (x)
e. 2.40 atm
f. 45.0 ml
2: ( n_1 )
3: ( t_1 )
4: ( p_2 )
5: ( v_2 )
6: ( t_2 )
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15.0 mL
Note: The final volume is calculated via the combined gas law $\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$, solving for $V_2=\frac{P_1V_1T_2}{P_2T_1}$. Assuming $T_2$ is 310 K (from option B, as the cut-off text implies this value), $V_2=\frac{0.800\ \text{atm} \times 45.0\ \text{mL} \times 310\ \text{K}}{2.40\ \text{atm} \times 295\ \text{K}} = 15.0\ \text{mL}$