Question

question 15 1 pts what is the balanced chemical equation for the reaction that takes place between br₂ and nai (sodium iodide)? br + nai₂ → nabri₂ br₂ + nai → nabr₂ + i br + nai₂ → nabr + i₂ br₂ + 2nai → 2nabr + i₂ question 16 1 pts which is the product(s) of this reaction? mg + n₂ → nmg mgn mg₂n₃ mg₃n₂

Explanation:

Step1: Analyze reaction type for Question 15

This is a single - displacement reaction. Bromine ($Br_2$) will displace iodine in sodium iodide ($NaI$).
The general form of a single - displacement reaction is $A + BC
ightarrow AC + B$. Here $A = Br_2$, $B = I$, and $C=Na$.
The balanced chemical equation is $Br_2 + 2NaI
ightarrow 2NaBr+I_2$.

Step2: Analyze reaction type for Question 16

Magnesium ($Mg$) reacts with nitrogen ($N_2$) to form magnesium nitride. Magnesium has a +2 oxidation state and nitrogen has a - 3 oxidation state in the compound.
Using the criss - cross method to find the formula of the compound formed between $Mg^{2 + }$ and $N^{3-}$, we get $Mg_3N_2$. The reaction is $3Mg + N_2
ightarrow Mg_3N_2$.

Answer:

Question 15: D. $Br_2 + 2NaI
ightarrow 2NaBr + I_2$
Question 16: D. $Mg_3N_2$