Question

question 16 using the equation al(oh)3 + 3hbr → albr3 + 3h2o, blank 1 moles of water would be produced from 2.49 moles of al(oh)3. blank 1 add your answer 5 points

Explanation:

Step1: Identify mole - ratio

From the balanced equation $\text{Al(OH)}_3 + 3\text{HBr}
ightarrow\text{AlBr}_3+3\text{H}_2\text{O}$, the mole - ratio of $\text{Al(OH)}_3$ to $\text{H}_2\text{O}$ is 1:3.

Step2: Calculate moles of water

Let $n_{Al(OH)_3}=2.49$ moles. Using the mole - ratio, $n_{H_2O}=3\times n_{Al(OH)_3}$.
$n_{H_2O}=3\times2.49$ moles.
$n_{H_2O} = 7.47$ moles.

Answer:

7.47