Question

1. $f(x) = 2^x$

$x$	$f(x)$
$-1$
$0$
$1$
$2$

Explanation:

Step1: Calculate \( f(-2) \)

Substitute \( x = -2 \) into \( f(x) = 2^x \). Using the rule \( a^{-n}=\frac{1}{a^n} \), we have \( f(-2)=2^{-2}=\frac{1}{2^2}=\frac{1}{4} \).

Step2: Calculate \( f(-1) \)

Substitute \( x = -1 \) into \( f(x) = 2^x \). Using the rule \( a^{-n}=\frac{1}{a^n} \), we get \( f(-1)=2^{-1}=\frac{1}{2^1}=\frac{1}{2} \).

Step3: Calculate \( f(0) \)

Substitute \( x = 0 \) into \( f(x) = 2^x \). By the rule \( a^0 = 1 \) (\( a
eq0 \)), we have \( f(0)=2^0 = 1 \).

Step4: Calculate \( f(1) \)

Substitute \( x = 1 \) into \( f(x) = 2^x \). So \( f(1)=2^1 = 2 \).

Step5: Calculate \( f(2) \)

Substitute \( x = 2 \) into \( f(x) = 2^x \). Then \( f(2)=2^2 = 4 \).

Answer:

\( x \)	\( f(x) \)
\( -1 \)	\( \frac{1}{2} \)
\( 0 \)	\( 1 \)
\( 1 \)	\( 2 \)
\( 2 \)	\( 4 \)