Question

question 18 1 point fred is examining the sodium consumed by americans. he collects data from 15 men with the data in milligrams below. find the mean for this set, using the ti-84. round to 4 decimal places if necessary. 512 1512 2937 2022 2861 2131 4626 1954 1327 4508 2954 3050 2905 1823 4883 provide your answer below:

Explanation:

Step1: Sum all the data values

First, we add up all the given data points: \(512 + 1512 + 2937 + 2022 + 2861 + 2131 + 4626 + 1954 + 1327 + 4508 + 2954 + 3050 + 2905 + 1823 + 4883\)

Let's calculate the sum:

\(512+1512 = 2024\)

\(2024+2937 = 4961\)

\(4961+2022 = 6983\)

\(6983+2861 = 9844\)

\(9844+2131 = 11975\)

\(11975+4626 = 16601\)

\(16601+1954 = 18555\)

\(18555+1327 = 19882\)

\(19882+4508 = 24390\)

\(24390+2954 = 27344\)

\(27344+3050 = 30394\)

\(30394+2905 = 33299\)

\(33299+1823 = 35122\)

\(35122+4883 = 40005\)

Step2: Divide the sum by the number of data points

There are 15 data points. So the mean \(\bar{x}=\frac{\text{Sum of data points}}{\text{Number of data points}}=\frac{40005}{15}\)

\(\frac{40005}{15}=2667\) (Wait, let's check the addition again because the initial addition might be wrong. Let's add the numbers correctly:

Let's list the numbers: 512, 1512, 2937, 2022, 2861, 2131, 4626, 1954, 1327, 4508, 2954, 3050, 2905, 1823, 4883

Let's group them to add:

(512 + 1512) = 2024

(2024 + 2937) = 4961

(4961 + 2022) = 6983

(6983 + 2861) = 9844

(9844 + 2131) = 11975

(11975 + 4626) = 16601

(16601 + 1954) = 18555

(18555 + 1327) = 19882

(19882 + 4508) = 24390

(24390 + 2954) = 27344

(27344 + 3050) = 30394

(30394 + 2905) = 33299

(33299 + 1823) = 35122

(35122 + 4883) = 40005

Wait, 40005 divided by 15: 15*2667 = 40005. So the mean is 2667.0000 (since it's an integer, rounded to 4 decimal places is 2667.0000)

Wait, but let's verify with the TI-84 method. To find the mean on TI-84:

1. Press STAT then EDIT
2. Enter the data into L1
3. Press STAT then CALC then 1-Var Stats
4. Select L1 (if data is in L1) and press ENTER

The mean (\(\bar{x}\)) will be calculated. Let's check the sum again. Wait, maybe I made a mistake in addition. Let's add all numbers:

512 + 1512 = 2024

2024 + 2937 = 4961

4961 + 2022 = 6983

6983 + 2861 = 9844

9844 + 2131 = 11975

11975 + 4626 = 16601

16601 + 1954 = 18555

18555 + 1327 = 19882

19882 + 4508 = 24390

24390 + 2954 = 27344

27344 + 3050 = 30394

30394 + 2905 = 33299

33299 + 1823 = 35122

35122 + 4883 = 40005

Yes, sum is 40005. Number of data points is 15. So 40005 / 15 = 2667. So the mean is 2667.0000 when rounded to 4 decimal places.

Answer:

2667.0000