Question

question 19
which are the product(s) of this chemical reaction? alcl₃ + 3nh₄oh →
o al(oh)₃ + 3nh₄cl
o 3alcl₃ + nh₄oh
o 3nh₄cl + 3aloh
o 3nh₄al + cl₃oh

question 20
which product of this chemical reaction (from the question above) is a solid? alcl₃ (aq) + 3nh₄oh (aq) →
o al(oh)₃
o nh₄cl
o alcl₃
o nh₄oh

Explanation:

Step1: Identify the reaction type

This is a double - displacement reaction. In a double - displacement reaction, the positive and negative ions of two ionic compounds exchange places.

Step2: Determine the products

For the reaction $\mathrm{AlCl}_{3}+3\mathrm{NH}_{4}\mathrm{OH}\to$, aluminum ($\mathrm{Al}^{3 + }$) combines with the hydroxide ion ($\mathrm{OH}^{-}$) and ammonium ion ($\mathrm{NH}_{4}^{+}$) combines with the chloride ion ($\mathrm{Cl}^{-}$). The balanced chemical equation is $\mathrm{AlCl}_{3}+3\mathrm{NH}_{4}\mathrm{OH}\to\mathrm{Al(OH)}_{3}+3\mathrm{NH}_{4}\mathrm{Cl}$.

Step3: Determine the solid product

According to solubility rules, most hydroxides are insoluble, and $\mathrm{Al(OH)}_{3}$ is a solid precipitate. Ammonium chloride ($\mathrm{NH}_{4}\mathrm{Cl}$) is soluble in water. $\mathrm{AlCl}_{3}$ and $\mathrm{NH}_{4}\mathrm{OH}$ are the reactants in aqueous form.

Answer:

Question 19: A. $\mathrm{Al(OH)}_{3}+3\mathrm{NH}_{4}\mathrm{Cl}$
Question 20: A. $\mathrm{Al(OH)}_{3}$