Question

question 5
20 pts
does this equation follow the law of conservation of mass? (yes or no)
3h₃po₄ + 6naoh → 6h₂o + 2na₃po₄

Explanation:

Step1: Count atoms on reactant side

For hydrogen ($H$): In $3H_3PO_4$, there are $3\times3 = 9$ $H$ - atoms, and in $6NaOH$, there are $6$ $H$ - atoms. So total $H$ - atoms on reactant side is $9 + 6=15$. For oxygen ($O$): In $3H_3PO_4$, there are $3\times4 = 12$ $O$ - atoms, and in $6NaOH$, there are $6$ $O$ - atoms. So total $O$ - atoms on reactant side is $12+6 = 18$. For phosphorus ($P$), there are $3$ $P$ - atoms in $3H_3PO_4$. For sodium ($Na$), there are $6$ $Na$ - atoms in $6NaOH$.

Step2: Count atoms on product side

For hydrogen ($H$): In $6H_2O$, there are $6\times2=12$ $H$ - atoms. For oxygen ($O$): In $6H_2O$, there are $6$ $O$ - atoms, and in $2Na_3PO_4$, there are $2\times4 = 8$ $O$ - atoms. So total $O$ - atoms on product side is $6 + 8=14$. For phosphorus ($P$), there are $2$ $P$ - atoms in $2Na_3PO_4$. For sodium ($Na$), there are $2\times3 = 6$ $Na$ - atoms in $2Na_3PO_4$.

Step3: Compare atom counts

The number of hydrogen and phosphorus atoms is not the same on both sides of the equation. So the equation does not follow the law of conservation of mass.

Answer:

no