Question

question 8 of 20
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what is the frequency (in khz) of photons with the energy of 374 j/photon?

Explanation:

Step1: Recall energy - frequency formula

The energy of a photon is given by $E = h
u$, where $E$ is the energy, $h$ is Planck's constant ($h=6.626\times 10^{- 34}\ J\cdot s$), and $
u$ is the frequency. We need to solve for $
u$.

Step2: Rearrange the formula for frequency

$
u=\frac{E}{h}$. Substitute $E = 374\ J$ and $h = 6.626\times 10^{-34}\ J\cdot s$ into the formula: $
u=\frac{374\ J}{6.626\times 10^{-34}\ J\cdot s}\approx5.64\times 10^{35}\ Hz$.

Step3: Convert Hz to kHz

Since $1\ kHz = 10^{3}\ Hz$, then $
u=\frac{5.64\times 10^{35}\ Hz}{10^{3}\ Hz/kHz}=5.64\times 10^{32}\ kHz$.

Answer:

$5.64\times 10^{32}$