Question

question 23
given the function $f(x)=2x^{2}-3x+5$. calculate the following values:
$f(-2)=$
$f(-1)=$
$f(0)=$
$f(1)=$
$f(2)=$
question help: video

Explanation:

Step1: Substitute $x=-2$ into $f(x)$

$f(-2)=2(-2)^2 - 3(-2) + 5 = 2(4) + 6 + 5$

Step2: Calculate $f(-2)$

$f(-2)=8 + 6 + 5 = 19$

Step3: Substitute $x=-1$ into $f(x)$

$f(-1)=2(-1)^2 - 3(-1) + 5 = 2(1) + 3 + 5$

Step4: Calculate $f(-1)$

$f(-1)=2 + 3 + 5 = 10$

Step5: Substitute $x=0$ into $f(x)$

$f(0)=2(0)^2 - 3(0) + 5 = 0 - 0 + 5$

Step6: Calculate $f(0)$

$f(0)=5$

Step7: Substitute $x=1$ into $f(x)$

$f(1)=2(1)^2 - 3(1) + 5 = 2(1) - 3 + 5$

Step8: Calculate $f(1)$

$f(1)=2 - 3 + 5 = 4$

Step9: Substitute $x=2$ into $f(x)$

$f(2)=2(2)^2 - 3(2) + 5 = 2(4) - 6 + 5$

Step10: Calculate $f(2)$

$f(2)=8 - 6 + 5 = 7$

Answer:

$f(-2)=19$
$f(-1)=10$
$f(0)=5$
$f(1)=4$
$f(2)=7$